The simple Java program finds duplicate characters in a given string and prints it as an output. There are two way to do it, first is by using nested loops and second one by sort method.
Suppose, we have given a string and asked us to dig out repeated characters and print over the screen. It is quite a tricky but its matter of fact how fast you build logic to find a solution.
Program:
public class RepeatedChar { public static void main(String[] args) { String str = "programmerbay"; char[] ch1 = str.toLowerCase().toCharArray(); int i, j, count; int len = ch1.length; System.out.println("Repeated characters in " + str); for (i = 0; i < len; i++) { count = 0; for (j = i + 1; j < len; j++) { if (ch1[i] == ch1[j]) { count++; } } if (count == 1) System.out.print(ch1[i] + " "); } } }
Output:
Repeated characters in programmerbay r a m
Program :
public class DuplicateChar { public static void main(String[] args) { String str = "programmerbay"; int flag = 0; char[] chrArr = str.toLowerCase().toCharArray(); Arrays.sort(chrArr); System.out.println(" Duplicate Characters in the given String : "); for (int i = 0; i < chrArr.length - 1; i++) { if (chrArr[i] == chrArr[i + 1]) { if (flag == 0) { System.out.println(chrArr[i]); } flag = 1; } else { flag = 0; } } } }
Output:
Duplicate Characters in the given String : a m r
This post was last modified on November 11, 2020