We usually see questions based on Mixtures and alligations in which two types of elements having cheaper and dearer costs are mixed together. In which you require to find the mean cost, the ratio of quantities in which they should be mixed in and much more.
Note:
Q. In what ratio must a grocer mix two varieties of pulses costing Rs. 15 and Rs. 20 per kg respectively so as to get a mixture worth Rs. 16.50 kg?
Cheaper quantity/ Dearer quantity = 3.5/1.5
= 7/3 = 7:3
Q. The cost of Type 1 rice is Rs. 15 per kg and Type 2 rice is Rs. 20 per kg. If both Type 1 and Type 2 are mixed in the ratio of 2 : 3, then the price per kg of the mixed variety of rice is:
Step 1 . 15 + 3 = 18 0r 20 -2 = 18
Answer Rs 18 per kg
Q. Tea worth Rs. 126 per kg, Rs. 135 per kg and Rs 175.5 per kg are mixed together. If the mixture is worth Rs. 153 per kg, then the ratio in which they mixed:
Step 1. Item A = 126 B =135 C =175.5
Possible pairs where mean value can 153 lie
(A and C), and (B and C)
Now Apply rule on these combinations
Step 2: A’s quantity = 22.5, B’s quantity = 22.5 and C is the same in group 1 and group 2, its quantity should be added ( 27 +18)
= Ratio = 22.5 : 22.5 :45
= 1: 1: 2
Q. Two vessels A and B contain spirit and water mixed in the ratio 5: 2 and 7: 6 respectively. Find the ratio in which this mixture be mixed to obtain a new mixture in vessel C containing spirit and water in the ratio 8: 5?
Step 1. A = 5:2 B = 7:6 C = 8:5
Choosing water as one of the ingrediant , so now
A = 2/7 , B = 6/13 C = 5/13
Step 2. Applying rule,
1/13 : 9/91
cross muliplication,
=91:117
=7:9
This post was last modified on July 4, 2022